rozwiaz równanie
x 1 x-6
----------+---------------=--------------------
x+3 x+2 x2+5x+6
zalozenie x≠-3,x≠-2
[x(x+2)+x+3-x+6]/(x²+5x+6)=(x²+2x+x+3-x+6)/(x+3)(x+2)=(x²+2x+9)/(x+3)(x+2)
delta mianownika=25-24=1
x1=-5-1/2=-3
x2=-5+1/2=-2
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zalozenie x≠-3,x≠-2
[x(x+2)+x+3-x+6]/(x²+5x+6)=(x²+2x+x+3-x+6)/(x+3)(x+2)=(x²+2x+9)/(x+3)(x+2)
delta mianownika=25-24=1
x1=-5-1/2=-3
x2=-5+1/2=-2