rozwiaz równanie.. to nawiasie to potega
a) 4x(5)+3x(4)-x(3)=0
b)x(3)-9x(2)+2x-18=0
a) 4x⁵+3x⁴-x³=0
x³(4x²+3x-1)=0
Δ=9+16=25
x₁=-3-5/8=-1
x₂=-3+5/8=1/4
x=0 v x=-1 v x=1/4
b)x³-9x²+2x-18=0
x²(x-9)+2(x-9)=0
(x-9)(x²+2)=0
x=9
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a) 4x⁵+3x⁴-x³=0
x³(4x²+3x-1)=0
Δ=9+16=25
x₁=-3-5/8=-1
x₂=-3+5/8=1/4
x=0 v x=-1 v x=1/4
b)x³-9x²+2x-18=0
x²(x-9)+2(x-9)=0
(x-9)(x²+2)=0
x=9