rozwiaz rownanie i nierownosc kwadratowa :
A)
x(x-5)=2x(x-1)
B)
3x-x^<3-3x^
A)x(x-5) = 2x(x-1)x^-5x = 2x^-2x / -2x^+2x-x^-3x = 0a=-1 b=-3 c=0delta=b^-4acdelta=(-3)^-4*(-1)*0delta=9pierwiastek z delty= 3x1=-b+pier. z delty/2ax1=3+3/2*(-1)X1=6/-2X1=-3X2=-b-pier. z delty/2ax2=3-3/2*(-1)
x2=0/-2
x2=0
a)
x²-5x=2x²-2x
-x²-3x=0
-x(x+3)=0
x=0 ∨ x=-3
b)
3x-x²<3-3x²
2x²+3x-3<0
Δ=3²-4*2*(-3)
Δ=9+24
Δ=33
√Δ=√33
x₁=(-3-√33)/(2*2)
x₁=(-3-√33)/4
x₂=(-3+√33)/(2*2)
x₂=(-3+√33)/4
x∈( (-3-√33)/4,(-3+√33)/4)
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A)
x(x-5) = 2x(x-1)
x^-5x = 2x^-2x / -2x^+2x
-x^-3x = 0
a=-1 b=-3 c=0
delta=b^-4ac
delta=(-3)^-4*(-1)*0
delta=9
pierwiastek z delty= 3
x1=-b+pier. z delty/2a
x1=3+3/2*(-1)
X1=6/-2
X1=-3
X2=-b-pier. z delty/2a
x2=3-3/2*(-1)
x2=0/-2
x2=0
a)
x(x-5)=2x(x-1)
x²-5x=2x²-2x
-x²-3x=0
-x(x+3)=0
x=0 ∨ x=-3
b)
3x-x²<3-3x²
2x²+3x-3<0
Δ=3²-4*2*(-3)
Δ=9+24
Δ=33
√Δ=√33
x₁=(-3-√33)/(2*2)
x₁=(-3-√33)/4
x₂=(-3+√33)/(2*2)
x₂=(-3+√33)/4
x∈( (-3-√33)/4,(-3+√33)/4)