rozwiaz rownanie: 1+9x^2+6x=0 Dam naj
9x^2 + 6x + 1 = 0
(3x)^2 + 2 * 3x * 1 + 1^2 = 0
(3x + 1)^2 = 0
3x + 1 = 0
3x = -1
x = -1/3
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9x^2 + 6x + 1 = 0
(3x)^2 + 2 * 3x * 1 + 1^2 = 0
(3x + 1)^2 = 0
3x + 1 = 0
3x = -1
x = -1/3