Rozwiaz nierownosci:
a) |x-4| < 3
b) |x+1| ≤ 2
c) + < 4-|x-4|
|x-4| < 3 |x-4| > - 3 x < 3 + 4 x > - 3 + 4 x < 7 x > 1
|x-4| < 3
x-4 < 3 lub x-4 > -3
x < 7 lub x > 1
|x+1| ≤ 2
x+1 ≤ 2 lub x+1 -2
x ≤ 1 lub x -1
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|x-4| < 3
|x-4| > - 3
x < 3 + 4
x > - 3 + 4
x < 7
x > 1
|x-4| < 3
x-4 < 3 lub x-4 > -3
x < 7 lub x > 1
|x+1| ≤ 2
x+1 ≤ 2 lub x+1 -2
x ≤ 1 lub x -1