Rozwiaż równanie:
podaj dziedzinę.
(2x+1)(5x-1) = 6x * (3x-1)
10x² - 2x + 5x - 1= 18x² - 6x
8x² - 9x + 1 = 0
Δ = (-9)² - 4*8*1 = 81 - 32 = 49
√Δ = 7
x₁ = 9-7/16 = ¹/₈
x₂ = 9+7/16 = 1
3x - 1 ≠ 0
3x ≠ 1
x ≠ ⅓
5x - 1 ≠ 0
5x ≠ 1
x ≠ ¹/₅
D = R \ {⅓,¹/₅}
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(2x+1)(5x-1) = 6x * (3x-1)
10x² - 2x + 5x - 1= 18x² - 6x
8x² - 9x + 1 = 0
Δ = (-9)² - 4*8*1 = 81 - 32 = 49
√Δ = 7
x₁ = 9-7/16 = ¹/₈
x₂ = 9+7/16 = 1
3x - 1 ≠ 0
3x ≠ 1
x ≠ ⅓
5x - 1 ≠ 0
5x ≠ 1
x ≠ ¹/₅
D = R \ {⅓,¹/₅}