Question

rozwiąż:

3(2x+1)-2y=-3(y+1)+5(x+2)-8

(x-2)(x+2)-(x-2)²=-y

(y+1)²-x(4x+2)=(y+2x)(y-2x)+3x²

Answer 1

3(2x+1)-2y=-3(y+1)+5(x+2)-8

6x+3-2y=-3y-3+5x+10-8

6x-5x=-3y+2y-3+10-8-3

x=y-2

 

(x-2)(x+2)-(x-2)²=-y

x²+2x-2x-4-x²+2x-2x-4=-y

-4=-y | *(-1)

y=4

 

(y+1)²-x(4x+2)=(y+2x)(y-2x)+3x²

y²+y+y+1-4x²+2x=y²-2xy+2xy-4x²+3x²

y²+2y-4x²+2x-y²+2xy-2xy+4x²-3x²=-1

2y+2x-3x²=-1