Question

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(x-3)²+(y+2)²=(x+3)²+(y-4)²

(x+4)²+(y-1)²=(x+2)²+(y+3)²

Answer 1

(x-3)²+(y+2)²=(x+3)²+(y-4)²

(x+4)²+(y-1)²=(x+2)²+(y+3)²

 

x²-6x+9+y²+4y+4 = x²+6x+9+y²-8y+16

x²+8x+16+y²-2y+1 = x²+4x+4+y²+6y+9

 

x²-x²+y²-y²-6x-6x+4y+8y+9+4-9-16 = 0

x²-x²+y²-y²+8x-4x-2y-6y+16+1-4-9 = 0

 

-12x+12y-12 = 0 |:12

4x-8y+4 = 0

 

-x+y-1 = 0

4x-8y+4 = 0

 

y = 1+x

4x-8*(1+x)+4 = 0

 

y = 1+x

4x-8-8x+4 = 0

 

y = 1+x

-4x-4 = 0

 

y = 1+x

4x = -4 |:4

 

y = 1+x

x = -1

 

y = 1-1

x = -1

 

y= 0

x = -1