October 2018 1 61 Report

rozwiąż układy dowolna metodą

\left \{ {{(2x-3)(2x+3)-4(x-5y)^{2}-3(x-y)=5x(4y-x)-(x-10y)^{2}+6x^{2}} \atop {\frac{2x-y}{2y-x}=0,1}} \right.

\left \{ {{\frac{-2}{x+4}=\frac{2}{y-5}} \atop {(x+3)^{2}-\frac{2y-18}{6}=(2+x)(x-2)+ \frac{2+3y}{3}+21 \frac{1}{3}}} \right.


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