rozwiąż układ równań2x+4y=2104x+2y=1804x+4y=?!
2x + 4y = 2104x + 2y = 180 |*22x + 4y = 210 | *(-1)8x + 4y = 360-2x - 4y = -2108x + 4y = 360----------------------2x + 8x - 4y + 4y = -210+3606x = 150 |:6x = 25x = 252x+4y = 210x = 252*25 + 4y = 210x = 2550 + 4y = 210x = 254y = 210-50x = 254y = 160 |:4x = 25y = 40Liczę na naj i pozdrawiamRaVVi
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2x + 4y = 210
4x + 2y = 180 |*2
2x + 4y = 210 | *(-1)
8x + 4y = 360
-2x - 4y = -210
8x + 4y = 360
---------------------
-2x + 8x - 4y + 4y = -210+360
6x = 150 |:6
x = 25
x = 25
2x+4y = 210
x = 25
2*25 + 4y = 210
x = 25
50 + 4y = 210
x = 25
4y = 210-50
x = 25
4y = 160 |:4
x = 25
y = 40
Liczę na naj i pozdrawiam
RaVVi