Rozwiąż układ równań.
{2x + ( 2 - y )^2 + y = 6 + y^2
{( x + y ) * ( x - 1 ) - 2( y - 2) * x + 3 = x * ( x - y )
Te dwie klamry to tjb jedna. Proszę o pomoc, to na jutro :(
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{2x+(2-y)²+y =6+y²
{( x+y )( x-1)-2(y-2)* x+3 = x*( x - y )
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{2x+4-4y+y²+y =6+y²
{x²-x+ xy-y -2yx+4x+3 = x²-xy
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{2x-3y=2
{3x-y=-3
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{2x-3y=2
{y=3x+3
2x-3(3x+3)=2
2x-9x+9=2
-7y=-7
y=1
x=2,5
{2x+(2-y)²+y=6+y²
{(x+y)·(x-1)-2(y-2)·x+3=x·(x-y)
{2x+4-4y+y²+y=6+y²
{x²+xy-x-y-2xy+4x+3=x²-xy
{2x-3y=2
{3x-y=-3
{y=3x+3
{2x-3(3x+3)=2
{y=3x+3
{2x-9x-9=2
{y=3x+3
{-7x=2+9
{-7x=11 /:(-7)
{x=-11/7=-1⁴/₇
{y=3·(-11/7) +3=-33/7 +3 =-4⁵/₇ +3 =-1⁵/₇