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x+y = -8
x = -8-y
(-8-y)²+y²+6(-8-y)+2y=0
64+16y+y²+y²-48-6y+2y =0
2y²+12y+16=0
Δ = b²-4ac = 144-128=16
√Δ=4
y₁= (-b-√Δ)/2a = (-12-4)/4 =-4
y₂= (-b+√Δ)/2a = (-12+4)/4 = -2
Czyli mamy dwa rozwiazania y₁=-4 i x₁ = -4, oraz y₂=-2. i x₂=-6