Rozwiąż układ równań metodą podstawiania lub przeciwnych współczynników.
(x-5)²-(x+2)²=7y
(y+4)²-(y-2)(y+2)=8x
x2 - 10x + 25 - (x2 +4x +4)=7y
y2 +8y +16 - (y2 - 4) =8x
x2- 10x +25 - x2 -4x -4 = 7y
y2 +8y +16 - y2 +4 =8x
-14x +21 = 7y
8y + 20 = 8x
-2x - y = -3
-2x +2y = -5
2x +y =3
-2x + 2y =-5
3y= -2
2x = 3-y
y=-2/3
2x= 3+2/3
2x=11/3
x=11/6
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x2 - 10x + 25 - (x2 +4x +4)=7y
y2 +8y +16 - (y2 - 4) =8x
x2- 10x +25 - x2 -4x -4 = 7y
y2 +8y +16 - y2 +4 =8x
-14x +21 = 7y
8y + 20 = 8x
-2x - y = -3
-2x +2y = -5
2x +y =3
-2x + 2y =-5
3y= -2
2x = 3-y
y=-2/3
2x= 3+2/3
y=-2/3
2x=11/3
y=-2/3
x=11/6