Rozwiąż układ równań
5(x-3y)=7(3y-x)
-3(x+4)+3(3-5y)=0
5(x-3y)=7(3y-x)
-3(x+4)+3(3-5y)=0
5(x-3y)=7(3y-x)
-3(x+4)+3(3-5y)=0
5x - 15y = 21y - 7x
5x + 7x = 21y + 15y
12x = 36y
wyznaczmy z tego rownania x
x = 36y : 12
x = 3y
wstawmy to teraz do rownania drugiego
-3(x+4)+3(3-5y)=0
-3(3y + 4) + 9 - 15y = 0
-9y - 12 + 9 - 15y = 0
-24y - 3 = 0
-24y = 3
y = -3/24
y = -1/8
x = 3y = 3(-1/8) = -3/8
-3(x+4)+3(3-5y)=0
5x - 15y = 21y - 7x
5x + 7x = 21y + 15y
12x = 36y
wyznaczmy z tego rownania x
x = 36y : 12
x = 3y
wstawmy to teraz do rownania drugiego
-3(x+4)+3(3-5y)=0
-3(3y + 4) + 9 - 15y = 0
-9y - 12 + 9 - 15y = 0
-24y - 3 = 0
-24y = 3
y = -3/24
y = -1/8
x = 3y = 3(-1/8) = -3/8
Zaloguj się by dodać komentarz
-3(x + 4) + 3(3 - 5y) = 0
5x - 15y = 21y - 7x
-3x - 12 + 9 - 15y = 0
5x + 7x - 15y - 21y = 0
-3x - 15y - 3 = 0
12x - 36y = 0 /:12
-3x - 15y = 3 /:3
x - 3y = 0
-x - 5y = 1
---------------- + (dodajemy stronami)
-8y = 1 /:(-8)
y = -¹/₈
x = 3 * (-¹/₈)
x = -³/₈
{x = -³/₈
{y = -¹/₈