Question

Rozwiąż układ równań

-(3x+y)²+(√3x-2)(√3x+2)=6y(1- x)-9x(x+2)+y(1-y)+10
-(√2y-2)(√2y+2)+3(x+y)=x(6-y)+xy

daje naj... z góry thx

Answer 1

-(3x+y)²+(√3x-2)(√3x+2)=6y(1- x)-9x(x+2)+y(1-y)+10
-(√2y-2)(√2y+2)+3(x+y)=x(6-y)+xy

-(9x²+6xy+y²)+3-4=6y-6xy-9x²-18x+y-y²+10
-(2-4)+3x+3y=6x-xy+xy

-9x²-6xy-y²-1=6y-6xy-9x²-18x+y-y²+10
-2+4+3x+3y=6x-xy+xy

-1=7y-18x+10
2+3x+3y=6x

-7y+18x=11
-2x+3y=-2

18x-7y=11
-2x+3y=-2/*9

18x-7y=11
-18x+27y=-18

20y=-7
y=-7/20

y=-7/20
-2x+3*(-7/20)=-2

y=-7/20
-2x-21/20=-2

y=-7/20
-2x=-2+21/20

y=-7/20
-2x=0,95

y=-7/20
x=-0,475