Rozwiąż równanie
x2+3x+2 = 0
(x2 - x kwadrat)
Δ= b² - 4ac = 3² - 4*1*2 = 9-8=1
√Δ = √1 = 1
x₁ = (-b-√Δ)/2a = (-3-1)/2 = -4/2 = -2
x₂ = (-b+√Δ)/2a = (-3+1)/2 = -2/2 = -1
x²+3x+2 = 0
Δ=9-8=1
√Δ=1
x₁=(-3-1)/2=-2
x₂=(-3+1)/2=-1
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x2+3x+2 = 0
Δ= b² - 4ac = 3² - 4*1*2 = 9-8=1
√Δ = √1 = 1
x₁ = (-b-√Δ)/2a = (-3-1)/2 = -4/2 = -2
x₂ = (-b+√Δ)/2a = (-3+1)/2 = -2/2 = -1
x²+3x+2 = 0
Δ=9-8=1
√Δ=1
x₁=(-3-1)/2=-2
x₂=(-3+1)/2=-1