Rozwiąż równanie:
x^2+3x-18=(2x-6)(2x-1)
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x²+3x-18=(2x-6)(2x-1)x² +3x-18= 4x² -2x-12x +6x² +3x-18 - 4x² +14x -6 = 0-3x² +17 x -24 = 0a = -3cb = 17c = -24Δ = 17² -4*(-3)*(-24) =289 -288 =1√Δ =1x₁ = (-17-1):(-3*2) =(-18):(-6) =3x₂ = (-17+1):(-3*2) =(-16):(-6) = 8/3= 2 i 2/3
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x²+3x-18=(2x-6)(2x-1)
x² +3x-18= 4x² -2x-12x +6
x² +3x-18 - 4x² +14x -6 = 0
-3x² +17 x -24 = 0
a = -3
cb = 17
c = -24
Δ = 17² -4*(-3)*(-24) =289 -288 =1
√Δ =1
x₁ = (-17-1):(-3*2) =(-18):(-6) =3
x₂ = (-17+1):(-3*2) =(-16):(-6) = 8/3= 2 i 2/3