Question

Rozwiąż równanie:

(x-3)(2x+2)=(x-3)(x²-6)

Answer 1

( x - 3)*( 2 x + 2) = ( x - 3)*( x^2 - 6)

( x - 3)*( 2 x + 2) - ( x - 3)*( x^2 - 6) = 0

( x - 3) *( 2 x + 2  - ( x^2 - 6)) = 0

( x - 3)*( - x^2  + 2 x + 8) = 0

x -3 = 0  lub   - x^2 + 2 x + 8 = 0

x = 3

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- x^2 + 2 x + 8 = 0

delta = 2^2 - 4*(-1)*8 = 4 + 32 = 36

p( delty) = p (36) = 6

x = [ - 2 - 6]/( -2) = - 8 / (-2) = 4

lub

x = [ - 2 + 6 ]/ ( -2) = 4/ ( -2) = -2

Odp. x1 = - 2, x2 = 3, x3 = 4

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