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Dla x<-1
-3(x+1)=2x²+4x
2x²+4x=-3x-3
2x²+7x+3=0
2x²+x+6x+3=0
x(2x+1)+3(2x+1)=0
(2x+1)(x+3)=0
2x+1=0 v x+3=0
x=-1/2∉D v x=-3
Dla x≥1
2x²+4x=3(x+1)
2x²+4x=3x+3
2x²+x-3=0
2x²-2x+3x-3=0
2x(x-1)+3(x-1)=0
(x-1)(2x+3)=0
x=1 v x=-3/2∈D
Odp. x∈ {-3, 1}