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(x-1)≠0⇒x≠1
(x-2)≠0⇒x≠2
D=R/{1,2}
obie strony równania mnożę przez (x-1)(x-2) otrzymuję
(x-1)(x-2)+x-2=2(x-1)
x²-2x-x+2+x-2=2x-2
x²-4x+2=0
Δ=16-8=8
√Δ=√8=2√2
x₁=(4-2√2)/2=2-√2
x₂=2+√2