rozwiąż równanie
x²-5x-24=0
Δ=b²-4ac
Δ=(-5)²-4*(-24)=25+96=121
√Δ=11
x1=(-b+√Δ)/2a
x1=(5+11)/2=16/2
x1=8
x2=(-b-√Δ)/2a
x2=(5-11)/2=-6/2
x2=-3
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x²-5x-24=0
Δ=b²-4ac
Δ=(-5)²-4*(-24)=25+96=121
√Δ=11
x1=(-b+√Δ)/2a
x1=(5+11)/2=16/2
x1=8
x2=(-b-√Δ)/2a
x2=(5-11)/2=-6/2
x2=-3