Question

Rozwiąż równanie
a)4x2(kwadrat)-9=0
b)-6xkwadrat+13x+5=0
c)2xkwadrat-9x-35=0
d)x do potegi 4 - 8x kwadrat + 16=0

Answer 1

a) (2x-3)(2x+3)=0

x=3/2   x=-3/2

 

b) delta = 169+120 = 289

x1=(-13-17)/-12 = 30/12 = 15/6=5/2

x2=(-13+17)/-12= 4/-12= -1/3

 

c) delta = 81+280=361

x1=(9-19)/4= -10/4= -5/2

x2=(9+19)/4= 28/4=7

 

d) x^2 = t

t^2 -8t+16 = 0

delta = 64-64=0

t0=8/2=4

Za t podstawiamy t0

x^2 = 4

x^2-4=0

(x-2)(x+2)=0

x=2  x=-2

Answer 2

rozwiazanie w zalaczniku