Rozwiąż równanie
a) (x-2)(x-5)(x+7)(x+12)=0
b) (2x-4)(x+3)(x-7)(8-x)=0
a)
(x-2)(x-5)(x+7)(x+12) = 0
x-2 = 0 => x = 2
lub
x-5 = 0 => x = 5
x+7 = 0 => x = -7
x+12 = 0 => x = -12
Odp. x = -12 v x = -7 v x = 2 x = 5
b)
(2x-4)(x+3)(x-7)(8-x)= 0
2x-4 = 0 /:2
x+3 = 0 => x = -3
x-7 = 0 => x = 7
8-x = 0 => x = 8
Odp. x = -3 v x = 2 v x = 7 v x = 8
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a)
(x-2)(x-5)(x+7)(x+12) = 0
x-2 = 0 => x = 2
lub
x-5 = 0 => x = 5
lub
x+7 = 0 => x = -7
lub
x+12 = 0 => x = -12
Odp. x = -12 v x = -7 v x = 2 x = 5
b)
(2x-4)(x+3)(x-7)(8-x)= 0
2x-4 = 0 /:2
x-2 = 0 => x = 2
lub
x+3 = 0 => x = -3
lub
x-7 = 0 => x = 7
lub
8-x = 0 => x = 8
Odp. x = -3 v x = 2 v x = 7 v x = 8