September 2018 1 77 Report

Rozwiąż równanie:

a) (n po 0) + (n po 1) + (n po 2) = 46, dla n należące do N i n≥2

b) (|x|-5)\sqrt{4-x^{2}}=0

c) x-3\sqrt{x-3}-13=0

wskazówka: x-3-3\sqrt{x-3}-10=0, gdzie x≥3

\sqrt{x-3}=t (t≥0)

t²-3t-10=0

d) x-2\sqrt{x+1}=14

ODP.:

a) n=9

b) -2, 2

c) x_{0}=28

d) x_{0}=24


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