Rozwiąż równanie
a)
b) x
c)
x(x-3)=(x+2)²-x²
x²-3x=x²+4x+4-x²
x²-7x-4=0
Δ=(-7)²-4*1*(-4)
Δ=49+16
Δ=65
√Δ=√65
x₁=(-(-7)-√65)/(2*1)
x₁=(7-√65)/2
x₂=(-(-7)+√65)/(2*1)
x₂=(7+√65)/2
b)
x²-7x=0
x(x-7)=0
x=0
x-7=0
x=7
5x²-15=0
5(x²-3)=0
x²-3=0
x²=3
x=√3 ∨ x=-√3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)
x(x-3)=(x+2)²-x²
x²-3x=x²+4x+4-x²
x²-7x-4=0
Δ=(-7)²-4*1*(-4)
Δ=49+16
Δ=65
√Δ=√65
x₁=(-(-7)-√65)/(2*1)
x₁=(7-√65)/2
x₂=(-(-7)+√65)/(2*1)
x₂=(7+√65)/2
b)
x²-7x=0
x(x-7)=0
x=0
x-7=0
x=7
c)
5x²-15=0
5(x²-3)=0
x²-3=0
x²=3
x=√3 ∨ x=-√3