Rozwiąż równanie:
a) -2x (x - 1) + 4 (2 + x) = 3 - 5x
b) x - 1 | 3 - x - 2 | 2 =
c) x - 2 | 3 - x + 10 | 8 =
d) x | x - 36 = 2 | 7
| - oznacza kreske ułamkową
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a) -2 (x - 1) + 4 (2 + x) = 3 - 5x
-2x + 2 + 8 + 4x = 3 - 5x | - 3
2x + 7 = - 5x | - 2x
7 = -7x |:(-7)
- 1 = x
b) x - 1 | 3 - x - 2 | 2 = x |* 6
6(x-1) / 3 - 6(x-2) / 2 = 6x
2x - 2 - 3x + 6 = 6x
- x + 4 = 6x | + x
4 = 7x | : 7
4/7 = x
c) x - 2 / 4 - x + 10 / 8 = 2x + 2 | * 8
8(x-2) / 4 - 8(x+10) / 8 = 16x + 16
2x - 4 - x - 10 = 16x + 16
x - 14 = 16x + 16 | - 16 -x
- 30 = 15x | : 15
- 2 = x
d) x / x - 36 = 2/7
x = 2(x - 36) / 7
x = 2x - 72 / 7 | * 7
7x = 2x - 72 | - 2x
5x = - 72 | : 5
x = - 14 2/5