Rozwiąż równanie:
(h+4)(2h-3)=2h(h+0,25)
2h^2-3h+8h-12=2h^2+0,5h
5h-0,5h=12
4,5h=12
h=2,6 (w zaokragleniu)
(h+4)/2h =(h+0,25)/(2h-3)
2h²+8h-3h-12=2h²+0,5h
2h²+8h-3h-2h²-0,5h=12
8h-3h-0,5h=12
h=12:4,5=12 :9/2 =12 · 2/9 =24/9 =2⅔
h=2⅔
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(h+4)(2h-3)=2h(h+0,25)
2h^2-3h+8h-12=2h^2+0,5h
5h-0,5h=12
4,5h=12
h=2,6 (w zaokragleniu)
(h+4)/2h =(h+0,25)/(2h-3)
(h+4)(2h-3)=2h(h+0,25)
2h²+8h-3h-12=2h²+0,5h
2h²+8h-3h-2h²-0,5h=12
8h-3h-0,5h=12
4,5h=12
h=12:4,5=12 :9/2 =12 · 2/9 =24/9 =2⅔
h=2⅔