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3(6^x+1)-6^x(6^x+1)>2*6^x
niech 6^x=z
3(z+1)-z(z+1)>2*z
3z+3-z²-z-2z>0
-z²+3>0
3-z²>0⇔z∈(-√3,√3)
z∈(0,√3)
6^x<√3