Rozwiąż równanie:
(√2x-1)(√2x+1)+3x-2=(3-x)²+x(x-1)
2x²-1+3x-2=9-6x+x²+x²-x
2x²+3x-3=9-7x+2x²
2x²-2x²+3x+7x-3-9=0
10x-12=0
10x=12
x=1,2
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(√2x-1)(√2x+1)+3x-2=(3-x)²+x(x-1)
2x²-1+3x-2=9-6x+x²+x²-x
2x²+3x-3=9-7x+2x²
2x²-2x²+3x+7x-3-9=0
10x-12=0
10x=12
x=1,2