Rozwiąż równanie:
1) 2x²-3x=0
2)x²-25=0
3)x²-3x-4=0
x(2x-3)=0
x=0 ∨ x=1½
x²=25
x=5 ∨ x=-5
Δ=(-3)²-4*1*(-4)=9+16=25
√Δ=5
x₁=(3+5)/2=8/2=4
x₂=(3-5)/2=-2/2=-1
x=4 ∨ x=-1
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1) 2x²-3x=0
x(2x-3)=0
x=0 ∨ x=1½
2)x²-25=0
x²=25
x=5 ∨ x=-5
3)x²-3x-4=0
Δ=(-3)²-4*1*(-4)=9+16=25
√Δ=5
x₁=(3+5)/2=8/2=4
x₂=(3-5)/2=-2/2=-1
x=4 ∨ x=-1