Rozwiąż równanie :
(x+3)do 2 - (y-1) do 2 . = (x-y)(x-y)
3x-7y=0
To jest jedno równanie.. pilsss.. daje naj ! ;)
(x+3)do 2 - (y-1)do2 =(x-y)(x-y)
(x+3)(x+3)-(y-1)(y-1)=(x-y)(x-y)
3x+7y=0
xdo2+3x+xdo2+3x-ydo2-y-y+1=xdo2-xy-xy+ydo2
2xdo2+6x-ydo2-2y+1=xdo2+2xy+ydo2
2xdo2+6x-2y-xdo2+2xy=1
xdo2+6x-2y+2xy=1
xdo2+9x+5y+2xy=1
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(x+3)do 2 - (y-1)do2 =(x-y)(x-y)
3x-7y=0
(x+3)(x+3)-(y-1)(y-1)=(x-y)(x-y)
3x+7y=0
xdo2+3x+xdo2+3x-ydo2-y-y+1=xdo2-xy-xy+ydo2
3x+7y=0
2xdo2+6x-ydo2-2y+1=xdo2+2xy+ydo2
3x+7y=0
2xdo2+6x-2y-xdo2+2xy=1
3x+7y=0
xdo2+6x-2y+2xy=1
3x+7y=0
xdo2+9x+5y+2xy=1