Question

Rozwiąż równanie:
x(2x^2-1)=0

Answer 1

[tex]x(2x^2-1)=0\\\\x=0\\\\2x^2-1=0\\2x^2=1\\x^2=\dfrac{1}{2}\\x=\sqrt{\dfrac{1}{2}} \vee x=-\sqrt{\dfrac{1}{2}}\\x=\dfrac{\sqrt2}{2} \vee x=-\dfrac{\sqrt2}{2}\\\\\boxed{x\in\left\{-\dfrac{\sqrt2}{2},0,\dfrac{\sqrt2}{2}\right\}}[/tex]

Answer 2

Odpowiedź:

x*( 2 x² - 1) = 0

x = 0   lub   2 x² - 1 = 0

x = 0   lub   2 x² = 1

x = 0   lub   x² = [tex]\frac{1}{2}[/tex]

x = 0   lub  x = - [tex]\frac{1}{\sqrt{2} }[/tex]    lub    x =  [tex]\frac{1}{\sqrt{2} }[/tex]

Odp.  x = 0   lub  x = - [tex]\frac{\sqrt{2} }{2}[/tex]    lub  x = [tex]\frac{\sqrt{2} }{2}[/tex]

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