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1/5x³+1/5x²-9/5x-9/5=0
1/5(x³+x²-9x-9)=0
x³+x²-9x-9
x²(x+1)-9x-9
x²(x+1)-9(x+1)
(x²-9)(x+1)
1/5(x²-9)(x+1)=0
x²-9=0
x²=9
x=3 v x=-3
x+1=0
x=-1
x∈{-1,3,-3}