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-x(x²+3x-4)=0
-x=0 lub x²+3x-4=0
x=0 lub x²+3x-4=0
∆=b²-4ac
∆=3²-4•1•(-4)=9+16=25
√∆= 5
x1=(-b-√∆):2a=(-3-5):2•1= -8:2= -4
x2=(-b+√∆):2a=(-3+5):2•1=2:2=1
Odpowiedź: x=0 lub x=-4 lub x=1