Question

Rozwiąż równanie : (x-1)(x+1)+x2-1+2x=2x-2 (x-4)2=(x-2)(x+2)+16 x2+(3x-3)(x+1)=(2x-1)2 (5x+6)2+37=(4x+6)2+(3x+5)2 -17+(3x+1)2=(4x+3)+9x2-(2x+3)

Answer 1

a)(x-1)(x+1)+x2-1+2x=2x-2

x2-1+x2-1+2x=2x-2

2x2-2+2x=2x-2

2x2=0 |:2

x2=0 | przez pierwiastek

x=0

 

b)(x-4)2=(x-2)(x+2)+16

x2-8x+16=x2-4+16

-8x=-4 |:-8

x=1/2

 

c)x2+(3x-3)(x+1)=(2x-1)2

x2+3x2+3x-3x-3=4x2-4x+1

4x2-3=4x2-4x+1

4x=4|:4

x=1

 

d)(5x+6)2+37=(4x+6)2+(3x+5)2

25x2+60x+36+37=16x2+48x+36+9x2+30x+25

25x2+60x-16x2-48x-9x2-30x=25-36+36-37

18x=-12|:18

x=-12/19

x=-2/3

 

e)-17+(3x+1)2=(4x+3)+9x2-(2x+3)

-17+9x2+6x+1=4x+3+9x2-2x-3

9x2+6x-4x-9x2+2x=3-3+17-1

4x=16 |:4

x=4