Question

Rozwiąż równanie x³-12x²+x-12=0

Answer 1

x³-12x²+x-12=0
x³+x-12x²-12=0
x(x²+1)-12(x²+1)=0

(x-12)(x²+1)=0

x=12

Answer 2

x³-12x²+x-12=0

x³+x-12x²-12=0

x(x²+1)-12(x²+1)=0

(x-12)(x²+1)=0

x-12=0          i                    x²+1=0

x=12                                 x²=-1 (nie możliwe)

odp. x=12