Question

Rozwiąż równanie : (x +1) ^ + 6x = (x - 1)^

_5_-_2_x_ = _4_ -_x_

3 2

_x_-_1_ = _x_+_2_

6 5

_2_-_3_x_ = _3_-_2_x_

4 5

^ - to znaczy do potęgi drugiej

_ _ _ _ - to jest kreska ułamkowa . Pomózcie mi plis :)

Answer 1

Rozwiąż równanie :

(x +1) ^ + 6x = (x - 1)^

x² + 2x + 1 + 6x = x² - 2x  +1

2x + 1 + 6x = -2x + 1

8x + 2x = 1 - 1

10x = 0

x = 0 : 10

x = 0

 

 

_5_-_2_x_  =  _4_ -_x_               /*6

        3                      2        

2(5 - 2x) = 3(4 - x)

10 - 4x = 12 - 3x

-4x + 3x = 12 - 10

-x = 2

x = -2

 

         

_x_-_1_ = _x_+_2_          /*30

      6                  5

5(x - 1) = 6(x + 2)

5x - 5 = 6x + 12

5x - 6x = 12 + 5

-x = 17

x = -17

 

 

     

   _2_-_3_x_ = _3_-_2_x_                  /*20

          4                         5

5(2 - 3x) = 4(3 - 2x)

10 - 15x = 12 - 8x

-15x + 8x = 12 - 10

-7x = 2

x = - 2 / 7

 

Answer 2

(x+1)^2 + 6x =(x-1)^2

x^2 +2x + 1 + 6x = x^2 -2x +1

10x =0  /:10

x=0

 

(5-2x)/3 = (4-x)/2

  2(5-2x) = 3(4-x)

  10 - 4x = 12 -3x

     -4x + 3x = 12-10

    -x = 2  /:(-1)

    x = -2

 

(x-1)/6 = (x+2)/5

5(x-1) = 6(x+2)

5x -5 = 6x +12

-x = 17   /:(-1)

x=-17

 

 

(2-3x)/4 = (3-2x)/5

4(3-2x) = 5(2-3x)

12 - 8x = 10 -15x

7x = -2  /:7

x = -2/7