Question

rozwiąż równanie wymierne

\frac{4x-3}{7+2x}=0

\frac{3}{4}={4x-11}{6x+2}

Answer 1

1.

(4x-3)/(7+2x) = 0

                                    Z: 7+2x ≠ 0

                                        2x ≠ -7  /:2

                                        x ≠ -3,5

                                    D = R \ {-3,5}

4x-3 = 0

4x = 3  /:4

x = 3/4

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2.

3/4 = (4x-11)/(6x+2) I*4(6x+2)

                                              Z: 6x+2 ≠ 0

                                                  6x ≠ -2  /:6

                                                  x ≠ -1/3

                                               D = R \ {-1/3}

3(6x+2) = 4(4x-11)

18x+6 = 16x-44

18x-16x = -44-6

2x = -50  /:2

x = -25

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