Odpowiedź:
[tex]\displaystyle \frac{3x^{2} -4x-4}{x-2} =1/\cdot(x-2)\qquad x\in R-\{2\}\\3x^{2} -4x-4=x-2\\3x^{2} -5x-2=0\\\Delta=25+24=49\qquad \sqrt{\Delta} =7\\x_1=\frac{5+7}{6} =2\notin D\qquad x_2=\frac{5-7}{6} =-\frac{2}{6} =-\frac{1}{3} \\\underline{x=-\frac{1}{3} }[/tex]
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Odpowiedź:
[tex]\displaystyle \frac{3x^{2} -4x-4}{x-2} =1/\cdot(x-2)\qquad x\in R-\{2\}\\3x^{2} -4x-4=x-2\\3x^{2} -5x-2=0\\\Delta=25+24=49\qquad \sqrt{\Delta} =7\\x_1=\frac{5+7}{6} =2\notin D\qquad x_2=\frac{5-7}{6} =-\frac{2}{6} =-\frac{1}{3} \\\underline{x=-\frac{1}{3} }[/tex]