Rozwiąż równanie : (ma wyjść 6⅓)
ale rozpiszcie to : D i z góry dziękuje : )
wszystko mnozymy przez 15 i wychodzi:
3(y-3) - 10(y-⅗) + 5 = 6 - 5 (2y-3)
3y - 9 - 10y + 6 + 5 = 6 - 10y + 15
-7y +2 = -10y +21
3y = 19
y=6⅓
1/5(y-3) -2/3(y-3/5)+1/3= 2/5 -1/3(2y-3)
1/5y -3/5 -2/3y +2/5 +1/3 = 2/5 -2/3y +1 /*15
3y - 9 -10y +6 +5 = 6 -10y +15
3y -10y +10y = 6 +15 +9 -6 -5
3y = 19 /:3
y = 19/3
y = 6i 1/3
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wszystko mnozymy przez 15 i wychodzi:
3(y-3) - 10(y-⅗) + 5 = 6 - 5 (2y-3)
3y - 9 - 10y + 6 + 5 = 6 - 10y + 15
-7y +2 = -10y +21
3y = 19
y=6⅓
1/5(y-3) -2/3(y-3/5)+1/3= 2/5 -1/3(2y-3)
1/5y -3/5 -2/3y +2/5 +1/3 = 2/5 -2/3y +1 /*15
3y - 9 -10y +6 +5 = 6 -10y +15
3y -10y +10y = 6 +15 +9 -6 -5
3y = 19 /:3
y = 19/3
y = 6i 1/3