Rozwiąż równanie kwadratowe: 2x^-9x=35
2x^2 - 9x=35
2x^2 -9x-35=0
delta= b^2 -4ac
delta= 81+280=361
pierw,z delty= 19
x1= -b+pierw,zdelty / 2a= 9+19/4=7
x2= -b-pierw.z delty/ 2a= 9-19/4=-10/4=-5/2=-2.5
2x²-9x-35=0
Obliczmy deltę:
Δ = b²-4·a·c
Δ = 81-4·2·(-35)
Δ = 81+ 280
Δ = 361
√Δ = 19
x₁ = (9-19)/4 = -2,5
x₂ = (9+19)/4 = 7
PS. W razie pytań pisz PW :)
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2x^2 - 9x=35
2x^2 -9x-35=0
delta= b^2 -4ac
delta= 81+280=361
pierw,z delty= 19
x1= -b+pierw,zdelty / 2a= 9+19/4=7
x2= -b-pierw.z delty/ 2a= 9-19/4=-10/4=-5/2=-2.5
2x²-9x-35=0
Obliczmy deltę:
Δ = b²-4·a·c
Δ = 81-4·2·(-35)
Δ = 81+ 280
Δ = 361
√Δ = 19
x₁ = (9-19)/4 = -2,5
x₂ = (9+19)/4 = 7
PS. W razie pytań pisz PW :)