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2x(x-3) = 0
x1 = 0 ∨ x2 = 3
b) 2x(x-3) = 0 (to samo co u góry)
x1 = 0 ∨ x2 = 3
c) 3x + 4x² = 0
Δ = b² - 4ac
Δ = 3² - 4(4*0) = 9
√Δ = 3
x1 = (-3-3)/8 = - = -
x2 = (-3+3)/8 = 0
d) 5x = 10x²
10x² - 5x = 0
5x(2x-1) = 0
x1 = 0 ∨ x2 =
2x(x-3)=0
x=0 lub x=3
b) 2x(x-3)=0
x=0 lub x=3
c) 3x+4x²=x(3+4x)
x=0 lub x=-3/4
d) 10x²-5x=0
5x(2x-1)=0
x=0 lub x=1/2