rozwiąż równanie 3x³-2x²-6x+4=0
3x³-2x²-6x+4=0
x²(3x-2)-2(3x-2)=0
(x²-2)(3x-2)=0
(x-2)(x+2)(3x-2)=0
x₁=2 x₂=-2 x₃=⅔
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3x³-2x²-6x+4=0
x²(3x-2)-2(3x-2)=0
(x²-2)(3x-2)=0
(x-2)(x+2)(3x-2)=0
x₁=2 x₂=-2 x₃=⅔
Pozdrawiam