Rozwiąż równanie : 2x^{3x} * 2x^{x-2} = 4x^{x+1}
to * oznacza że pomnożone
6x² * 2x² - 4x= 4x² + 4x
12x² - 4x = 4x² + 4x/+4x
12x²= 4x² + 8x/-4x²
8x² = 8x/:8
x²=x/: √
x= √x
Chyba tak :)
2x^{3x} * 2x^{x-2} = 4x^{x+1}
2x^{3x}*2x^{x-2}=2^{2}x^{x+1}
2x^{3x}*2x^{x-2}= 2x^{2x+2}
2x^{3x+x-2}=2x^{2x+2}
2x^{4x-2}=2x^{2x+2}
mamy te same podstawy wiec:
4x-2=2x+2
4x-2x=2+2
2x=4
x=2
licze na naj
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6x² * 2x² - 4x= 4x² + 4x
12x² - 4x = 4x² + 4x/+4x
12x²= 4x² + 8x/-4x²
8x² = 8x/:8
x²=x/: √
x= √x
Chyba tak :)
2x^{3x} * 2x^{x-2} = 4x^{x+1}
2x^{3x}*2x^{x-2}=2^{2}x^{x+1}
2x^{3x}*2x^{x-2}= 2x^{2x+2}
2x^{3x+x-2}=2x^{2x+2}
2x^{4x-2}=2x^{2x+2}
mamy te same podstawy wiec:
4x-2=2x+2
4x-2x=2+2
2x=4
x=2
licze na naj