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x²(2x-3) - 2(2x-3)=0
(2x-3)(x²-2)=0
(2x-3)(x+√2)(x-√2)=0
2x-3=0 v x+√2=0 v x-√2=0
x=3/2 v x=-√2∉D v x=√2
Odp. x∈{√2, 1,5|
2x^3 - 3x^2 - 3 + 9 - 4x = 0
2x^3 - 3x^2 - 4x + 6 = 0
x^2(2x-3) - 2(2x-3) = 0
(2x-3)(x^2-2) = 0
(2x-3)(x-√2)(x+√2) = 0 ⇒
2x-3 = 0 lub x-√2=0 lub x+√2 = 0
x = 1,5 lub x = √2 ≈ 1,42 lub x = - √2 ≈ -1,42
Odp.: x= { √2, 1,5}