Rozwiąż rownanie: (2x-3)(2x+3)=(x+5)kwadrat-9
4x^-9=x^+10x+25-9 ^ do kwadratu
4x^-x^-10x-25=0
3x^-10x-25=0
delta= (-10)^-4*3*(-25)
delta=100+300
delta= 400
pierwiastek z delty=20
x1= (10-20)/2
x1=-5
x2=(10+20)/2
x2=15
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4x^-9=x^+10x+25-9 ^ do kwadratu
4x^-x^-10x-25=0
3x^-10x-25=0
delta= (-10)^-4*3*(-25)
delta=100+300
delta= 400
pierwiastek z delty=20
x1= (10-20)/2
x1=-5
x2=(10+20)/2
x2=15