Question

Rozwiąż równanie
1)100x²-9(x+1)²=0
2)25(x+2)²-16=0

Answer 1

1)100x²-9(x+1)²=0
100x² -9(x² + 2x + 1) = 0
100x² -9x² - 18x -9 =0
91x² - 18x -9 =0
Δ=b²-4ac
Δ=324 -364*(-9)
Δ=324 + 3276
Δ= 3600
√Δ = 60

x1 = -b -√Δ / 2a = -91 - 60 / 182 = - 151/182
x2 = -b +√Δ /2a = -91 + 60 /182 = 31 /182

2)25(x+2)²-16=0
25x² + 100x + 84 = 0
Δ=b²-4ac
Δ=1000 - 100*84
Δ=1000 - 8400
Δ= -7400
delta ujemna brak rozwiązań

Answer 2

1)100x²-9(x+1)²=0
100x²-9(x²+1)=0
100x²-9x²-9=0
91x²=9
91x=3
x=0,03