Question

rozwiąż równanie. 1 ( 3x-1)(X2-49)=0 2 8x3=125​

Answer 1

Zadanie 1.

[tex]( 3x-1)(x^2-49)=0\\3x-1=0\ \vee\ x^2-49=0\\3x=1\ |:3\ \vee\ x^2=49\\x=\frac{1}{3}\ \vee\ x=7\ \vee\ x=-7\\x\in\{-7,\frac{1}{3},7\}[/tex]

Zadanie 2.

[tex]8x^3=125\ |:8\\x^3=\frac{125}{8}\\x=\sqrt[3]{\frac{125}{8}}\\x=\frac{5}{2}\\x=2\frac{1}{2}[/tex]

Answer 2

[tex]a)\\(3x-1)(x^{2} -49)=0\\3x-1=0\vee x^{2} -49=0\\3x=1\vee x^{2} =49\\x=\frac{1}{3} \vee x=7\vee x=-7[/tex]

[tex]b)\\8x^{3} =125/:8\\x^{3}=\frac{125}{8} /\sqrt[3]{} \\x=\sqrt[3]{\frac{125}{8} } =\frac{5}{2}[/tex]