Rozwiąż równania:
a) x^{3}-2x^{2}-9x+18=0
b) x^{4}-x^{3}-2x^{2}=0
c) x^{3}-x^{2}-9x+9=0
d) (2x-5)(x^{2}+3x-4)=0
tamtych nie umiem
a) x³-2x²-9x=-18
-x-9x=-18
-10x=-18/ : (-10)
x=18/10 = 1 8/10
b) -2x=0/:(-2)
x=0
c)x³-x²-9x=-9
x-9x=-9
-8x=-9/ : (-8)
x= 9/8 = 1 1/8
d) 2x³+6x²-8x-5x²-15x+20=0
2x³+6x²-8x-5x²-15x=-20
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(x - 2)(x^2 - 9) = 0
(x - 2)(x -3)(x + 3) = 0
x = 2 lub x = 3 lub x = -3 ------> to jest odpowiedź
tamtych nie umiem
a) x³-2x²-9x=-18
-x-9x=-18
-10x=-18/ : (-10)
x=18/10 = 1 8/10
b) -2x=0/:(-2)
x=0
c)x³-x²-9x=-9
x-9x=-9
-8x=-9/ : (-8)
x= 9/8 = 1 1/8
d) 2x³+6x²-8x-5x²-15x+20=0
2x³+6x²-8x-5x²-15x=-20