Rozwiąż Równania
a) (x-2)2 = x2
b) (2x+2)2 =4x(x-4
Jakby Co
x2-ta dwójka po x to jest do kwadratu
prosze o rozpisanie tego
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a) (x-2)²= x²
x²-4x+4= x²
-4x=-4
x=1
b) (2x+2)² =4x(x-4)
4x²+8x+4=4x²-16x
32x=-4
x=-1/8
^ - potęga
A.
(x-2)(x-2) = x^2
x^2 + 4x +4 = x^2
-4x = -4 //-4
x = 1
B.
(2x+2)(2x+2)= 4x (x-4)
4x^2 + 4x + 4x + 4 = 4x^2 - 16x
8x + 16x = -4
24x = -4 // 24
x= -1/6